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Old 27-03-06, 22:43
Leif Leif is offline  
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Join Date: Jan 2006
Location: Luton
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Quote:
Originally Posted by Ledaig
Leif,

The following is based on a 500mm long, 32mm diameter tube with a 2.00mm wall thickness.

The basis for the calculation is a weight reduction, expressed as a percentage of the original mass of the tube, based on 10 holes drilled in varying diameters from 2.00mm up to 20.00 (inclusive).

Further calculations can be made by multiplying the number of holes accordingly.

2.00mm……….0.07%
4.00mm……….0.27%
6.00mm……….0.60%
8.00mm……….1.08%
10.00mm……….1.69%
12.00mm……….2.45%
14.00mm……….3.36%
16.00mm……….4.44%
18.00mm……….5.68%
20.00mm……….7.12%

Hope this helps.

Cheers,
Steve

Steve. Thanks. It does look like it is not really worth doing. Leif
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